- Published on
Larger Number At Least Twice of Others
- Authors
- Name
- ShoxruxC
- @iOSdasturchi
📝 Vazifa tavsifi
Sizga butun sonlardan iborat nums massivi berilgan. Agar massivdagi eng katta element boshqa barcha elementlardan kamida ikki marta katta bo'lsa, uning indeksini qaytaring. Aks holda -1 qaytaring.
Misol:
Input: nums = [3,6,1,0]
Output: 1
Tushuntirish: Eng katta element 6 (indeks 1). 6 >= 2*3, 6 >= 2*1, 6 >= 2*0. Shart bajarilgan.
Largest Number At Least Twice of Others
Oson10 daqiqa10 ball
📚 Misollar
Kiruvchi: nums = [3,6,1,0]
Chiquvchi: 1
Kiruvchi: nums = [1,2,3,4]
Chiquvchi: -1
func solve(_ nums: [Int]) -> Int {
// Kodingizni shu yerga yozing
return -1
}
Run tugmasini bosing